I have the following function implementation
function getRepo(url) {
var repos = {};
if (repos.hasOwnProperty(url)) {
return repos[url];
}
return $.get(url)
.then(repoRetrieved)
.fail(failureHandler);
function repoRetrieved(data) {
return repos[url] = data;
}
function failureHandler(err, xhr) {
throw new Error(xhr.responseText);
}
}
And i wrote the following tests:
describe('"getRepo" method', function() {
var getDeffered;
var $;
beforeEach(function() {
getDeffered = Q.defer();
$ = jasmine.createSpyObj('$', ['get']);
$.get.and.returnValue(getDeffered.promise);
});
it('should return a promise', function(){
expect(getRepo('someURL')).toEqual(getDeffered.promise);
});
});
And this test fails. I think because i call the then method.
It does not fail if function implementation is:
function getRepo(url) {
return $.get(url);
}
this is the message jasmine throws when using Q.defer()
Expected { promiseDispatch : Function, valueOf : Function, inspect : Function }
to equal { promiseDispatch : Function, valueOf : Function, inspect : Function }.
And this is the message if i use jQuery Deferred:
Expected { state : Function, always : Function, then : Function, promise : Function, pipe : Function, done : Function, fail : Function, progress : Function }
to equal { state : Function, always : Function, then : Function, promise : Function, pipe : Function, done : Function, fail : Function, progress : Function }.
jQuery Deferred test implementation:
describe('"getRepo" method', function() {
var getDeffered;
var $;
beforeEach(function() {
getDeffered = real$.Deferred();
$ = jasmine.createSpyObj('$', ['get']);
$.get.and.returnValue(getDeffered.promise());
});
it('should return a promise', function(){
expect(getRepo('someURL')).toEqual(getDeffered.promise());
});
});
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