Mocking assert_called_with in Python

I'm having some trouble understanding why the following code does not pass:

test.py

import mock
import unittest

from foo import Foo


class TestFoo(unittest.TestCase):
    @mock.patch('foo.Bar')
    def test_foo_add(self, Bar):
        foo = Foo()
        foo.add(2, 2)
        Bar.add.assert_called_with(2, 2)


if __name__ == '__main__':
    unittest.main()

foo.py

from bar import Bar

class Foo(object):
    def add(self, x, y):
        bar = Bar()
        return bar.add(x, y)

bar.py

class Bar(object):
    def add(self, x, y):
        print('b.Bar --> Adding {} + {}'.format(x, y))
        return x + y

In the code, Foo.add creates an instance of Bar and returns the result of Bar.add when invoked. Why does testing assert_called_with for Bar.add fail? I believe I am mocking the Bar in the correct place (I am mocking foo.Bar because that is the namespace which it is being looked up, rather than bar.Bar).

Traceback (most recent call last): File "/Users/iain/PycharmProjects/testing/venv/lib/python2.7/site-packages/mock.py", line 1201, in patched return func(*args, **keywargs) File "test.py", line 12, in test_a_b fake_Bar.add.assert_called_with(2, 2) File "/Users/iain/PycharmProjects/testing/venv/lib/python2.7/site-packages/mock.py", line 831, in assert_called_with raise AssertionError('Expected call: %s\nNot called' % (expected,)) AssertionError: Expected call: add(2, 2) Not called